Arm/loadexec

Write a function that will copy a block of code (assumed to be a function) to a given location in memory, then call the function, passing it one integer parameter.

void loadexec( int(*dest)(int), int(*src)(int), unsigned int code_length, int param);

The block of code is located at location src, with length code_length bytes. This block of code should be copied to dest. After copying, execute the code at dest and pass it parameter param, and returning its return value (i.e., with dest as a function pointer, do return dest(param))

Expected solution length: Around 10 lines.

Sample Input

[See below]

Sample Output

r0=8

// Some testing code
// When debugging in CPUlator, turn off the following debugging checks:
// - Instruction fetch: Modified opcode
// - Instruction fetch: Outside a code section (If Dest is outside the .text section)

Src: 
	add r0, r0, r0	// This function returns double its parameter.
	bx lr
Dest:
	.skip 8		// Make space for the code

.global _start
_start:
	ldr r0, =Dest
	ldr r1, =Src
	ldr r2, =8	// There are 2 instructions to copy: 8 bytes
	ldr r3, =4	// Let's call the function with parameter 4
	bl loadexec
	1: b 1b  // done

// Your function starts here:
loadexec:

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